I was reading this post explaining why $S_n$ embeds into $A_{n+2}$. So they suggest that the embedding schould be
$Sn \hookrightarrow A_{n+2}$
$\sigma \mapsto \sigma$ if $\sigma$ is even and
$\sigma \mapsto \sigma (n+1, n+2)$ if $\sigma$ is odd. Could I multiply by any transposition in the case where $\sigma$ is odd or is it important to take $(n+1, n+2)$?
Asked
Active
Viewed 87 times
1
Bernard
- 179,256
roi_saumon
- 4,406
1 Answers
2
If you multiply by another transposition the function might not be a homomorphism. The reason why it works with $(n+1,n+2)$ is because this specific transposition commutes with any permutation $\sigma\in S_n$.
Mark
- 43,582
-
Oh I see, thanks, I only thought about injectivity – roi_saumon Jan 16 '19 at 21:49