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In the title, $\gamma$ is the Euler-Mascheroni constant and $\Gamma(3/4)$ represents the extension of the factorial function.

This isn't a homework question or something, someone left it on a board in one of the buildings in my university and I'm just really surprised by it. The only thing I've tried is writing out the first few terms and trying to manipulate them into some sort of pattern, but I don't see where to go from there.

$$\frac{\ln{3}}{3}-\frac{\ln{5}}{5}+\frac{\ln{7}}{7}-\frac{\ln{9}}{9}+...$$ $$\ln{(3^{1/3})}-\ln{(5^{1/5})}+\ln{(7^{1/7})}-\ln{(9^{1/9})}+...$$ $$\ln{\Bigg(\frac{3^{1/3}}{5^{1/5}}\Bigg)}+\ln{\Bigg(\frac{7^{1/7}}{9^{1/9}}\Bigg)}+...$$

From here, I know that I could combine log terms even more, multiplying the numerators/denominators, but I don't think that's the right path to follow for this.

clathratus
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