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What are the main techniques for proving that the solutions of ODE are defined for all times? Obviously I refer to qualitative study of $$y'=f(t,y)$$ with $f:\mathbb{R}\times\mathbb{R}^n\to\mathbb{R}^n $ at least $C^0$. The standard way is to use classical reults (e.g. prove that $f$ is sublinear or globally lipschitz) but these rusults are often not applicable. In this case I try to show that the solutions are bounded (it is known that if the orbits are bounded then the solutions are defined for all time). To do this I usually try one of the following techniques:

  • I look for a constant of the motion and I study the level sets to understand the shape of the orbits (and see if they are bounded);

  • I find a particular solution that is a closed and curve (e.g. a circle): in fact for the uniqueness the orbits can not intersect and therefore all orbits that start from inside this closed curve will have to remain there and will therefore be limited;

  • I study the function $h(t): = x^2(t) + y^2(t)$: I make the derivative and I try to show that it is limited;

  • I try a change of variables (e.g. polar coordinates) that simplifies the equations.


In conclusion:

1) Do you know other general techniques to show that the orbits are bounded?

2) However, boundedness is only a sufficient condition to prove that solutions are defined for all time! In case the solutions are unbounded how can I prove that they are defined for all time? For example consider $$\begin{cases}\dot x=-y^2\\ \dot y = x^2\end{cases}$$ or $$\begin{cases}\dot x=y^2\\ \dot y = x^2\end{cases}$$ The level sets of the constants of motion ($E:=x^3\pm y^3$) of these system are open and unbounded curve. In this case the only techniques that I know is to cumpute $t=\int^{+\infty}_{x_0}...dx$ and understand if this integral converges or diverges (for other details see the end of this page: Qualitative study of $ \dot x = - y^2$, $\dot y= x^2 $).

3) Advice on books and readings about this problem are welcome.

Ef_Ci
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  • The simplest approach and really the standard, if there is one: Gronwall. – John B Jul 03 '18 at 21:40
  • @JohnB it's included in the case "$f(t,y)$ sublinear in $y$". – Ef_Ci Jul 03 '18 at 21:44
  • The first and third approaches can be subsumed under Lyapunov function. – user539887 Jul 03 '18 at 21:44
  • @user539887 good idea! Thanks. – Ef_Ci Jul 03 '18 at 21:46
  • If you have some compact domain and vector field points inside of it along its boundary, this also guarantees that solutions that start on boundary are defined for all $ t \geqslant 0$. Also, I remember a theorem which states that you can always transform a system of differential equations in such way that it has the same integral curves as an original one, but there is no finite time blow-up. Sadly, I can't find a reference with this theorem right now. – Evgeny Jul 05 '18 at 07:25
  • @Evgeny I tried to find a reference for the autonomous case on an open set (see Any differential equation has a complete reparametrization), and the only thing I found is Mariano Suárez-Álvarez' more than five-year-old answer to “Completing” a vector field on a non-compact manifold M: it uses quite advanced methods in differential geometry. – user539887 Jul 05 '18 at 20:36
  • @user539887 I vaguely remember that this thing for $\mathbb{R}^n$ was called something like "Vinograd regularization", but googling this didn't help. If I'm not mistaking anything, the method was basically to go from $\dot{x} = F(x)$ to $\dot{u} = F(u)/\sqrt{1 + | F(u) |^2}$. But I still can't find where I've seen this trick or is it even working. – Evgeny Jul 05 '18 at 20:41
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    @user539887 By the way, I kind of found the reference: in Nemytskii-Stepanov book (p.19) there is Vinograd theorem which states that reparameterization that makes vector field complete exists. However, they do it differently than I remembered. At least some reference exists :) – Evgeny Jul 05 '18 at 20:52
  • @Evgeny A very good reference. – user539887 Jul 05 '18 at 21:16
  • @Evgeny Could you give some information on that paper [55] by P. E. (rather R.E.?) Vinograd in Nemytskii-Stepanov book? I don't have access to the bibliography. – user539887 Jul 21 '18 at 10:39
  • @user539887 Me neither at this moment. I even can't find some pdf to check what was that reference. Russian version doesn't have it as far as I can see. – Evgeny Jul 22 '18 at 15:44

1 Answers1

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An answer to 1):

In mathematical population biology, a totally competitive system of ODEs is defined as $$ x'_i = x_i f_i(x_1, \dots, x_n), \quad i = 1, \dots, n, $$ where $$ \frac{\partial f_i}{\partial x_j} < 0 $$ (of course $f_i$ are assumed to be $C^1$, at least). The natural phase space is the nonnegative orthant $C = \{\, x = (x_1, \dots, x_n) : x_i \ge 0$ for all $i = 1, \dots, n \,\}$.

As $x_i$ represents the population density of the $i$-th species, only solutions that are bounded for positive time have biological significance. There is a very simple, but extremely useful, sufficient condition for such boundedness:

For each $i = 1, \dots, n\ $ there is $x_i^* > 0$ such that $f_i(0, \dots, 0, x_i^*, 0, \dots, 0) = 0$.

Indeed, let $x \in C$ be such that for some $j$, $x_j > x_j^*$. Then $$ f_j(x) = f_j(x_1, \dots, x_{j-1}, x_j, x_{j+1}, \dots, x_n) \le f_j(0, \dots, 0, x_j, 0, \dots, 0) < f_j(0, \dots, 0, x_j^*, 0, \dots, 0) = 0. $$ From this it follows that all solutions are attracted toward the ($n$-dimensional) parallelepiped $[0, x_1^*] \times \ldots \times [0, x_n^*]$. Consequently, each solution in $C$ is defined for all positive times $t$.

For (much) more on such systems, see, e.g., Zhao's book Dynamical Systems in Population Biology. See also the classical paper by M. W. Hirsch Systems of differential equations which are competitive or cooperative: III. Competing species.

user539887
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  • I do not work in the field of mathematical population biology but your example is interesting. Thanks for your support. – Ef_Ci Jul 04 '18 at 10:27