-1

Can anyone give a simple example for it? [![enter image description here][1]][1]

[1]: https://i.sstatic.net/d3KiB.jpg . Please expalin the example shown in pic.

1 Answers1

1

What you have written down is that a normed linear space is an inner product space if and only if the parallelogram law holds. For a simple example of a normed spaced that is not an inner product space, consider the space of real-valued continuous functions on $[0,1],$ with norm $$\|f\|=\sup_{x\in[0,1]}|f(x)|$$ It is easy to see that this is a real vector space and to verify that $\|\cdot\|$ is a norm.

To see that it is not an inner product space we just need one example where the parallelogram law fails. Take $f(x)=x,\ g(x)=x^2.$ Then $\|f\|=\|g\|=1,\ \|f+g\|=2,\ \|f-g\|=1/4,$ and one can check that the parallelogram law does not hold.

saulspatz
  • 53,824