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Could someone clarify this question?

Assume that inter-arrival times of student arriving at the canteen are exponentially distributed with a mean of $\dfrac13$.

a) Find the probability that no students arrive during a $20$ minutes interval.

b) Find the probability that more than two students arrive during the server's ten-minute break.

For part (a), how would I find the the probability of $x=0$ students when exponential distribution only works for $x$ less or equal to a number? Do I need to use Poisson?

For part (b) how would I go about using the break time? It doesn't make sense to me.

an4s
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Wonder Women
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    Exponential inter-arrival times is equivalent to Poisson arrivals. As to your second question, it's just a 10-minute interval like any other. – saulspatz Apr 28 '18 at 19:21
  • @saulspatz why is equivalent to Poisson arrivals? does that mean I plug in 0 in Poisson equation? probability is 0.7165? – Wonder Women Apr 28 '18 at 19:31
  • https://math.stackexchange.com/questions/183760/what-is-the-correct-inter-arrival-time-distribution-in-a-poisson-process – saulspatz Apr 29 '18 at 05:06

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