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I have a characterisitic function of the form $e^{(-\alpha t + t^2)}\sum_{j=0}^\infty C_j t^j $, where $\alpha, C_j$'s are complex constants. I am trying to find the probability distribution for this characteristic function.

Had the characteristic function just been of the form $e^{(-\alpha t + t^2)} $, the integration would have been simply

\begin{align} \int_{-\infty}^\infty e^{(-\alpha t + t^2)} e^{-itx} dx &= \int_{-\infty}^\infty e^{-(t^2 + (\alpha + ix)t)} dx \\ &= e^{(\frac{(\alpha+ix)}{2})^2} \int_{-\infty}^\infty e^{-(t+\frac{(\alpha+ix)}{2})^2} dx \end{align}

Using clues from this answer, I think the integral evaluates to some constant. However, having this extra term $\sum_{j=0}^\infty C_j t^j$ troubles me with the integration as I cannot proceed with the above approach.

Can you please help me out. Thank you!

honeybadger
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1 Answers1

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Dealing with the $\sum_{j=0}^\infty C_j t^j$ terms is pretty straightforward, if one understands the fact that characteristic function of $\frac{d^n f(x)}{dx^n}$ is $(it)^n\hat{f(t)}$

honeybadger
  • 1,197