Prove that for any integer $n$, we have $n^3=n \text{ in } Z_6$
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Yes, what did you try? (It's also rather easy to just test all six cases one-by-one.) – Parcly Taxel Dec 06 '17 at 11:40
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$$n^3-n=(n+1)n(n-1)$$ – lab bhattacharjee Dec 06 '17 at 11:43