If $Y$ is not connected, $Y$ is union of nonempty seperated set $A$,$B$. Since $X$ is connected, Then $X \subset A$ or $X \subset B$. If $X \subset A$ then $\overline X \subset \overline A$ But since $A$, $B$ is seperated, $\overline A \cap B$ is empty and $B \subset \overline A$, so $B = \varnothing$, which derive a contradiction.
From this StackExchange answer.
I follow up until "$B \subset \overline A$". Why is this true?