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Then B is the basis for a half-open topology denoted by T" in R.

Show that (R,T") is first countable but not second countable.

How can I prove it ?

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  1. For real $r$ consider $\{[r,r+q): r<q\in \mathbb Q\}.$

  2. If $C$ is any base for $T''$ then for each real $r$ there exists $f(r)\in C$ such that $r\in f(r)\subset [r,r+1).$ Consider $\{f(r): r\in \mathbb R\}.$