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Let $L/K$ be a Galois extension of number fields. We know that if $Q,Q'$ are two primes of $L$ lying over a prime $P$ of $K$, then

  1. e$(Q|P)$=e$(Q'|P)$ (the ramification indices are same )
  2. f$(Q|P)$=f$(Q'|P)$ (the inertia degrees are same )

My question is this: Is the converse true ?

If $L/K$ is an extension which has the following property:

Let $P$ be any prime of $K$. If $Q$ and $Q'$ are primes of $L$ lying over $P$ then

  1. e$(Q|P)$=e$(Q'|P)$ (the ramification indices are same )
  2. f$(Q|P)$=f$(Q'|P)$ (the inertia degrees are same )

Can we say that $L/K$ is Galois extension ?

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