I was confuse about how to prove this ~~ My thought is prove the N(T) is finite dimension first then use this property to get R(T) is closed
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This is wrong. $T:\ell^2\to\ell^2$, $(x_n)_{n\in\mathbb N} \mapsto (x_n/n)_{n\in\mathbb N}$ is compact with dense range.
Jochen
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I know how to prove it ~~ thx for answer
– Chun-yen Wu Mar 09 '16 at 07:37