Its known that newton's interpolation and lagrange interpolation gives the same value All i need is to prove it
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That's because there exist a unique interpolating polynomial, no matter what method you use to compute it. – Crostul Mar 03 '16 at 22:19
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@Crostul yeah i already know that all im asking about is proof that if i use lagrange or newton i'll get the same value – Mena ebn magdy Mar 03 '16 at 22:21
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Let $N$ be the polynomial you get with Newton, and $L$ the polynomial you get with Lagrange. They are interpolating polynomials, hence they are equal. – Crostul Mar 03 '16 at 22:24
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There is a unique polynomial of degree $\leq$ (number of points - 1) going through the points. Lagrange and Newton both produce such a thing, therefore the same thing.
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