Evaluate the following limit
$\lim\limits_{n \to \infty} n \sin(2\pi \;e \;n!)$
I have no idea how to proceed forward?
Answer for above is $2\pi$ but I don't know how this comes about.
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7See http://math.stackexchange.com/questions/76097/what-is-the-limit-of-n-sin-2-pi-cdot-e-cdot-n-as-n-goes-to-infinity – lab bhattacharjee Feb 22 '16 at 08:54
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For problems like this where you have $n!$ in the limit and $n\to\infty$, using Stirling's result helps most of the time. – learner Feb 22 '16 at 09:02
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@ lab bhattacharjee thanks i got it. – PAMG Feb 22 '16 at 09:11
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@ learner ok thanks. – PAMG Feb 22 '16 at 09:12