Suppose there is a $3$ dimensional space and transformation that
- transforms zero into zero
- preserves distance between any two points
Prove:
- transformation is linear
- transformation is invertible
- According to definition:
$$\begin{array}{l}f(x + y) = f(x) + f(y)\\\alpha f(x) = f(\alpha x)\end{array} $$
How I can try to prove it in this context?
There is the proof from external resource:
- Introduce inner product:
$$(x,y) = \frac{{{{\left\| {x + y} \right\|}^2} - {{\left\| {x - y} \right\|}^2}}}{4} = xy $$
it's defined with distance only(preserved from our second axiom) $\Rightarrow $ inner product is preserved $\Rightarrow $ angles preserved
construct matrix A: columns - basis vectors, they are orthogonal, they form an orthonormal system
${A^T}A = A{A^T} = E $ because multiply orthogonal vectors (1 only if multiply by itself)
we explicitly find ${A^{-1}} \Rightarrow$ transformation is invertible
Questions:
Why inner product has this form? Why not simple $(x,y) = $$\left\| {x + y} \right\| $
Why columns of matrix $A$ form orthonormal system?