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Every infinite Hausdorff space has a countably infinite discrete subspace.

Now I know $R$ under usual topology has $Z$ and under "lower limit topology" also has $Z$ as such. So goes on for $R^{n}$ as long as $n$ is finite it will be $Z^{n}$ .But what about general Hausdorff Spaces? Please some hints.

I need to know what such discrete subspaces might look like for $R^{inf}$ since $Z^{\inf}$ or $N^{\inf}$ are not countable.

user118494
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  • The other link was helpful. It has the proof but I also need the answer for $R^{\inf }$ which is not asked there. So please someone kindly give some hints about the countably infinite discrete subspace of $R^{\inf}$. – user118494 Jul 20 '15 at 21:16

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