Paper with proof that $L=\{ a^n b^n \mid n \geq 0 \} \cup \{ a^n b^{2n} \mid n \geq 0 \}$ is not Deterministic Context Free?

Question

These lecture slides sketch a proof that $L=\{ a^n b^n \mid n \geq 0 \} \cup \{ a^n b^{2n} \mid n \geq 0 \}$ cannot be accepted by any Deterministic Pushdown Automaton. Unfortunately, the slides give no references as to where the proof comes from.

I was wondering, does anybody know of an academic paper or textbook that gives a full proof? I'd love to be able to cite it, but I haven't been able to find one.

score 6 · Accepted Answer · answered May 30 '13 at 01:30

6

The result is proved in Ginsburg and Greibach, Deterministic context free languages, Inform. Control 9(6), 620–648, 1966, Theorem 4.1 on page 24 (643). However, the proof looks somewhat different.

answered May 30 '13 at 01:30

Yuval Filmus

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Paper with proof that $L=\{ a^n b^n \mid n \geq 0 \} \cup \{ a^n b^{2n} \mid n \geq 0 \}$ is not Deterministic Context Free?

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