On page 2 of this article, there is example of FEAL-4.
At round 2, the input to F (Round Function) is 0x80800000. As F accepts only 4 bytes I divide the input by 2 so that (As I assume the result will be 8 bytes firstly) I compute 8080 and after 0000, concating two results will be 8 bytes:
0x8080|0000
x0x1x2x3|x0x1x2x3
1).8080
y1=G1(8,8)
y2=G1(y1,8)
y0=G0(x0,y1)
y3=G1(y2,0)
Counting G0/G1
G0(a,b)=(a+bmod256<<<2)
G1(a,b)=(a+b+1mod256<<<2)
G1(8,8)=(11mod256<<<2)=44 y1
G0(8,44)=(4cmod256<<<2)=130 y0
G0(8,44)=(4cmod256<<<2)=130 y2
G1(130,0)=(131mod256<<<2)=4C4 y3
But even after this the result is not matching as on the slide (round2) it should be 0x02000000. Is it a mistake ? Thanks!
