Convert.ToInt32(string) giving wrong values

Question

I am getting weird numbers when I am parsing my string using the convert.toint32

var check = "82567";
Convert.ToInt32(check[0]) //I get 56
Convert.ToInt32(check[0].ToString());// I get 8

Can someone help me make sense of this

Both are right. check[0] is a character, the int value is its ascii code, 8 in a string is 8 so returns 8 — BugFinder, Oct 18 '19 at 10:24

score 5 · Accepted Answer · answered Oct 18 '19 at 10:26

check[0] is a single character -- the character '8'. This means that you call the Convert.ToInt32(char) overload, which:

returns a 32-bit signed integer that represents the UTF-16 encoded code unit of the value argument

'8' has the value 56.

check[0].ToString() returns a string, and so you call Convert.ToInt32(string), which returns:

A 32-bit signed integer that is equivalent to the number in value, or 0 (zero) if value is null

score 3 · Answer 2 · answered Oct 18 '19 at 10:26

There's nothing wrong here.

Your first call is to Convert.ToInt32(char) which just promotes the char to int. The value of check[0] is a char with a value of 56 - the UTF-16 value of '8'.

Your second call is to Convert.ToInt32(string) which parses the string as a number. The string "8" is parsed to the value 8.

Convert.ToInt32(string) giving wrong values

2 Answers2