How to set a child process name in subprocess?

Question

I want to set a name to the child process spawned by subprocess module.

subprocess.Popen(["ls"]) spawns child process named ls, but I want to set a custom name of the process. For example, if I open top instead of process showed by name ls, it will be showed by custom name e.g. list-all-files set by me. How can I do that by using subprocess module or any other way?

http://stackoverflow.com/questions/564695/is-there-a-way-to-change-effective-process-name-in-python — gnr, Sep 20 '14 at 16:50
@gnr: that's about changing the process name *from within the process*. — Martijn Pieters, Sep 20 '14 at 16:53

score 0 · Answer 1 · answered Sep 21 '14 at 15:24

How about using a link and aliasing?

user@localhost: ln -s /bin/ls list-all-files
user@localhost: alias ls list-all-files

When you now run subprocess.Popen(['ls']) you'll only see a process list-all-files running in a ps/top.

Otherwise a bash wrapper might be a good way to go.

How to set a child process name in subprocess?

1 Answers1