Questions tagged [rank-1-matrices]
83 questions
82
votes
3 answers
Eigenvalues of the rank one matrix $uv^T$
Suppose $A=uv^T$ where $u$ and $v$ are non-zero column vectors in ${\mathbb R}^n$, $n\geq 3$. $\lambda=0$ is an eigenvalue of $A$ since $A$ is not of full rank. $\lambda=v^Tu$ is also an eigenvalue of $A$ since
$$Au = (uv^T)u=u(v^Tu)=(v^Tu)u.$$…
user9464
49
votes
3 answers
A rank-one matrix is the product of two vectors
Let $A$ be an $n\times m$ matrix. Prove that $\operatorname{rank} (A) = 1$ if and only if there exist column vectors $v \in \mathbb{R}^n$ and $w \in \mathbb{R}^m$ such that $A=vw^t$.
Progress: I'm going back and forth between using the definitions…
coconutbandit
- 493
26
votes
6 answers
Rank of sum of rank-$1$ matrices
If you sum a certain number of rank-$1$ matrices:
$$X = u_1 u_1^T + u_2 u_2^T + \cdots + u_N u_N^T$$
Is the result guaranteed to be rank-$N$ assuming the individual $U$ vectors are linearly independent?
gct
- 623
13
votes
5 answers
Characteristic polynomial of a matrix of $1$'s
I am trying to calculate the characteristic polynomial of the $n \times n$ matrix $A = \{ a_{ij} = 1 \}$.
Case $n=2$: I obtained $p(\lambda)=\lambda^2-2\lambda$ .
Case $n=3$: I obtained $p(\lambda)=-\lambda^3+3\lambda^2$.
Case $n=4$: I obtained…
Thom Kostova
- 447
10
votes
1 answer
Cones of positive semidefinite matrices generated by matrices of rank $1$
Let $S_n$ be the space of real $n \times n$ symmetric matrices and let $S_n^+$ be the convex cone of positive semidefinite matrices in $S_n$. The extremal rays of this cone correspond to the positive semidefinite matrices of rank $1$.
My problem is…
Max
- 121
10
votes
1 answer
Convex hull of rank-$1$ matrices is the nuclear norm unit ball
Let
$$A := \left\{ u v^T : u \in \mathbb{R}^m, v \in \mathbb{R}^n, \|u\|_2 = \|v\|_2 = 1 \right\}$$
I would like to show that
$$\textrm{conv}(A) = B_* := \left\{ X \in \mathbb{R}^{m \times n}: \|X\|_* = \textrm{Tr} \left( \sqrt{XX^T} \right) \le 1…
guanton
- 365
9
votes
1 answer
What properties does a rank-$1$ matrix have?
I have seen a lot of papers mentioning that a certain matrix is rank-$1$. What properties does a rank-$1$ matrix have?
I know that if a matrix is rank-$1$ then there are no independent columns or rows in that matrix.
Matthew
- 319
9
votes
2 answers
Singularity of a conic combination of rank-$1$ matrices
Given rank-$1$ square matrices $A_1, A_2, \dots, A_n$, determine if there exists $x \in \mathbb R_{>0}^n$ such that
$$ \sum_{i=1}^n x_i A_i = x_1 A_1 + \cdots + x_n A_n $$
is singular, or decide whether none exists (i.e., the positive linear…
M.A
- 450
8
votes
3 answers
Calculating the minimal polynomial of a rank-$1$- matrix
Given the matrix $$ \begin{pmatrix} 1 & 1 & \dots & 1 \\ 2 & 2 & \cdots & 2 \\ \vdots & \vdots & \ddots & \vdots \\ n & n & \dots & n \end{pmatrix} $$ calculate the minimal polynomial.
I know that the characteristic polynomial is
$$ P_A(x) =…
TheNotMe
- 4,899
7
votes
4 answers
$\det(I+A)=1+\operatorname{Tr}(A)$ if $\operatorname{rank}(A)=1$
Let $A$ be a complex matrix of rank $1$. Show that $$\det (I+A) = 1 + \operatorname{Tr}(A)$$ where $\det(X)$ denotes the determinant of $X$ and $\operatorname{Tr}(X)$ denotes the trace of $X$.
Any hint, please. I do not get how to combine the…
user598858
7
votes
4 answers
Some basic questions regarding rank-$1$ matrices
If an $n \times n$ matrix $B$ has rank $1$, and $A$ is another $n \times n$ matrix, then why does $A B$ also have rank $1$? This showed up in a solution that I read through, but it doesn't seem like an obvious fact.
And one more thing that came up…
User001
- 1
6
votes
4 answers
How can I solve "average" best rank-$1$ approximation?
Assume I want to minimise this
$$ \min_{x,y} \left\| A - x y^T \right\|_{\text{F}}^2$$
then I am finding best rank-$1$ approximation of $A$ in the squared-error sense and this can be done via the SVD, selecting $x$ and $y$ as left and right singular…
Thomas Arildsen
- 397
5
votes
3 answers
Optimal symmetric rank-1 approximation
I want to find $\mathbf{x}$ that minimizes $\|A-\mathbf{x}\mathbf{x}'\|^2$ where $\|\cdot\|$ is Frobenius norm.
Differentiating with respect to $\mathbf{x}$ and setting to $\mathbf{0}$, I get
$$\mathbf{x}\mathbf{x}'\mathbf{x}=A \mathbf{x}$$
Any…
Yaroslav Bulatov
- 5,579
4
votes
1 answer
Minimal "dominating" rank-$1$ matrix
Given a matrix ${\bf A} \in \Bbb R^{n \times n}$, I would like to find a minimal rank-$1$ matrix ${\bf B} \in \Bbb R^{n \times n}$ such that the Frobenius norm of $ \| {\bf A} - {\bf B} \|_{\text{F}} $ is minimal under the constraint of $ a_{ij}…
Jiro
- 579
4
votes
1 answer
Finding the best rank-one approximation of the matrix $\bf A$
I have computed the singular value decomposition (SVD) of the following matrix $A$.
$$ {\bf A} := \begin{bmatrix}1&2\\0&1\\-1&0\\\end{bmatrix} = \underbrace{\left[\begin{matrix}0 & \sqrt{\frac 5 6} & \frac{1}{\sqrt 6} \\ \frac{1}{\sqrt 5} &…
jh123
- 1,438