We can calculate the factorials of whole ( positive) numbers, factorials of fractions whose denominators are $2$ i.e. $\left(1/2\right)!$,
- but can we also calculate $\left(1/3\right)!$, $\left(2/3\right)!$ and $\left(1/6\right)!$ ?.
- If yes, what are they ?. Do they also contain the square root of $\pi$, or maybe some other cool constant ?. How can we do that ?.
- I am familiar with $\Gamma\left(x\right)$ and $\Pi\left)(x\right)$, but not with the incomplete gamma function.
If not, why not ?.
$$\cos(x)=\frac{\pi}{\left(-\frac{x}{\pi}-\frac{1}{2}\right)! \left(\frac{x}{\pi}-\frac{1}{2}\right)!}$$
After some simplification I did just now I got:
$$\sin(x)=\frac{\pi}{\left(-\frac{x}{\pi}\right)! \left(\frac{x}{\pi}-1\right)!}$$ $$\sin(\pi x)=\frac{\pi}{\left(-x\right)! \left(x-1\right)!}$$ $$\left(-x\right)! \left(x-1\right)!=\frac{\pi}{\sin(\pi x)}$$
– DefinitelyNotADolphin Nov 21 '24 at 17:25I fantasized that I was the first person to discover it, and that it would be a breakthrough in maths, but independently discovering something is definitely not what I'd ever expect.
– DefinitelyNotADolphin Nov 21 '24 at 17:34