The second to last equality is just an application of the change of variables formula. The original integral is performed with respect to ${\bf x}:= (x_1,x_2,\ldots,x_N)$ and we wish to change variables from $\bf x$ to ${\bf u}:=(u_1,\ldots,u_N)$ via the mapping
$$u_1:=F_1(x_1),\quad u_2:=F_2(x_2),\quad\ldots,\quad u_N:= F_N(x_N).\tag1$$ By the change of variables formula, we can write
$$\int h({\bf x})\,d{\bf x}=\int h({\bf x}({\bf u})){\left|{\det \left(\frac{\partial {\bf x}}{\partial{\bf u}}\right)}\right|}\,d{\bf u}
=
\int
\frac{h({\bf x}({\bf u}))}{\left|{\det \left(\frac{\partial {\bf u}}{\partial{\bf x}}\right)}\right|}\,d{\bf u}.$$
For the mapping (1) the Jacobian determinant is easily seen to be
$$\left|{\det \left(\frac{\partial {\bf u}}{\partial{\bf x}}\right)}\right|=\prod_{i=1}^N p_i(x_i),
$$
which immediately yields the desired equality.