I've been working on this problem and I'm stuck on this part, I need to factorize this polynomial in the field of integers modulo 5
$f(x)=(x^5-x)^2-1$
And so far I've gotten that by difference of squares that it can be factored into $$f(x)=(x^5-x-1)(x^5-x+1)$$
However from here I cannot really tell for sure this two polynomials are irreducible, I know (Because of the solution that they are), but I can't justify it, I've thought of trying to use Eisenstein but it's not applicable and there are too many irreducible polynomials to try them out one by one
Is there something I'm missing?
Thank you in advance!