I am studying classical mechanics and I was asked in my homework to calculate poisson brackets of components of angular momentum. I couldn't understand how to approach, then I looked at the solution. I found: \begin{align*} \epsilon_{\alpha\beta\gamma}\epsilon_{\gamma\mu\nu} x_\beta p_\nu + \epsilon_{\alpha\beta\gamma}\epsilon_{\beta\mu\nu} x_\nu p_\gamma &= \left(\epsilon_{\alpha\beta\gamma}\epsilon_{\gamma\mu\nu} + \epsilon_{\alpha\gamma\nu}\epsilon_{\gamma\mu\beta}\right) x_\beta p_\nu \end{align*} I still don't understand how they factored out the expression of $x_\beta p_v$. What have they exactly done?
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2It should suffice to change name to the summation variables in the second term, essentially exchanging $\nu\leftrightarrow\beta$ first, and then $\nu\leftrightarrow\gamma$ – Giulio R Dec 17 '22 at 17:19
2 Answers
As I'm sure you're aware, the Einstein summation convention is in force, meaning that any index appearing twice in the same term is to be summed over. The name of that index is irrelevant. Whether it is called $\mu$ or $\beta$ doesn't matter as long as the name of that index is unique to the term. Sometimes these are called “dummy indices;” I prefer “summation indices” to avoid the ableist connotation.
In the second term of the expression on the left-hand side, $\epsilon_{\alpha\beta\gamma}\epsilon_{\beta\mu\nu} x_\nu p_\gamma$, the only non-summation indices are $\alpha$ and $\mu$. In order to combine this term with the previous, we would like to have the same name of the indices on $x$ and $p$ ($\beta$ and $\nu$, respectively). So we rename the $\nu$ on $x$ to $\beta$. Of course, we have to replace the other appearances of $\nu$ with $\beta$ too. At the same time, we rename the $\gamma$ on $p$ by $\nu$, and change all the other appearances as well.
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I think this is just re-labeling the second term. In before:after notation, you want $ν:β$ and $γ:ν$ to be able to factor out the last two factors. Now to close the loop, one could add $β:γ$, so lets see $$ before:~~ϵ_{αβγ}ϵ_{βμν}x_νp_γ \\ after:~~ϵ_{αγν}ϵ_{γμβ}x_βp_ν $$ Yes, that fits exactly.
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Thanks! So every time i'd want to do that i'll need to "close the loop"? – Itay2924 Dec 17 '22 at 17:39
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Not necessarily. You can also introduce a completely new variable that replaces $γ:\kappa$, but then again that could be thought of as closing the loop "outside" the formula as $\kappa:γ$. This more linear substitution chain might influence how easy the next steps are. – Lutz Lehmann Dec 17 '22 at 17:44