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This is a problem from 2017 Bulgaria Selection Test for the Junior Balkan Mathematical Olympiad:

Given a triangle $\triangle ABC$ and $AA_1$, $BB_1$ are angle bisectors. If angle $AA_1B_1$ = $24^{\circ}$, angle $BB_1A_1$ = $18^{\circ}$.Find out the other angles of the triangle .

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So - Angle C can be easily deduced with basic geometry . But from here the trouble begins - I tried various constructions (like, trying to get the angles in a parallelogram or something). At last, I got the answer by using sine law repeatedly.

But this wasn’t satisfactory for me as I always work with pure Euclidean way of geometry . By using trigonometry - I many have got the answer but not the required satisfaction .

Hence, I asked my colleagues, tried myself over a Month ( I don’t like to give up ) and here I am. Anybody with a pure geometry ( Euclid geometry ) proof. You have my appreciation .

Krosin
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This is a trigonometric solution.I want help on how to solve it geometrically

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