A Greatest Common Divisor Property

Asked Jun 24 '13 at 03:56

Active Jun 24 '13 at 04:44

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Show that: If $c|a^m-1$ and $c|a^n-1$ then $c|a^{gcd(m,n)}-1$

edited Jun 24 '13 at 04:44

asked Jun 24 '13 at 03:56

Nicole

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