Let $\phi: \Bbb P^1 \to \Bbb P^1$ be a rational map then we define $Aut(\phi)=\{f \in PGL_2(\Bbb C): f^{-1}\phi f(z)=\phi(z)\}$
Here, in general, the definition of a rational map is: Let $\mathbb{P}^n$ and $\mathbb{P}^m$ be projective spaces. If $m$ homogeneous polynomials in $n+1$ variables of the same degree "d" give a partially defined map from $\mathbb{P}^n$ to $\mathbb{P}^m$ then this map is called a rational map. We can exactly define this on a projective variety as well.
Now for $\mathbb{P}^1$ we can prove that:
Let $\phi: \Bbb P^1 \to \Bbb P^1$ be a rational map of degree $d \geq 2$. Then $Aut(\phi)$ is a finite subgroup of $ PGL_2(\Bbb C)$ and its order is bounded by a function of $d$.
This proof can be done by using the fact that $f\in PGL_2(\Bbb C)$ is basically a Mobius transformation and once it fixes three points it is constant and once we know this result we can manipulate the periodic points of $\phi$ to have an upper bound. If you ask for details I can fill in the gaps.
The problem arises if we go to higher dimension say $\mathbb{P}^2$ or $\mathbb{P}^n, n\geq 2$. Then we will have at least 3 homogeneous polynomials in at least $3$ variables of the same degree. Can we extend this result and have some bounds? Any hint or result would be much appreciated. Even if you give some sequential hints I can try to fill the gaps and reach out for help in the comments.