Let $\vec{F}(x, y, z)$ be a vector-valued function describing a vector-field. Then the rotation and divergence of the field are:
$\nabla \times \vec{F} = \text{curl}(\vec{F}) = \color{red}{(\frac{\partial{F_3}}{\partial{y}} - \frac{\partial{F_2}}{\partial{z}}, \frac{\partial{F_1}}{\partial{z}} - \frac{\partial{F_3}}{\partial{x}}, \frac{\partial{F_2}}{\partial{x}} - \frac{\partial{F_1}}{\partial{y}})}$
$\nabla \cdot \vec{F} = \text{div}(\vec{F}) = \color{blue}{\frac{\partial{F_1}}{\partial{x}} + \frac{\partial{F_2}}{\partial{y}} + \frac{\partial{F_3}}{\partial{z}}} $
if the elements involved in the above relations are placed in a matrix, one gets:
$A= \begin{bmatrix} \color{blue}{\frac{\partial{F_1}}{\partial{x}}} & \color{red}{\frac{\partial{F_1}}{\partial{y}}} & \color{red}{\frac{\partial{F_1}}{\partial{z}}} \\ \color{red}{\frac{\partial{F_2}}{\partial{x}}} & \color{blue}{\frac{\partial{F_2}}{\partial{y}}} & \color{red}{\frac{\partial{F_2}}{\partial{z}}} \\ \color{red}{\frac{\partial{F_3}}{\partial{x}}} & \color{red}{\frac{\partial{F_3}}{\partial{y}}} & \color{blue}{\frac{\partial{F_3}}{\partial{z}}} \end{bmatrix}$
Isn't the above matrix the gradient, $\text{grad}$, of $\vec{F}$?
Isn't this how a Jacobian looks like?
Additionally, this matrix could be represented as the sum of a diagonal and antisymmetric matrices, then, the elements of the $\text{curl}$ are elements of an antisymmetric matrix and those of $\text{div}$ are the trace of a diagonal matrix.
If valid, what are all these three matrices called?
Could it be said that $\text{curl}(\vec{F})$ measures how "unsymmetrical" is the matrix A?
I get the sense from your question that -- when you wrote it five years ago! -- you might have been just learning vector calculus. I could imagine not getting a response being a bit demoralizing. But I think it was quite insightful of you. I've worked with Jacobians on a daily basis for nearly a decade (albeit not in a context that motivates this kind of question) and hadn't noticed this before today.
– colah May 29 '23 at 02:04