A cone $K$, where $K ⊆\Bbb R^n$ , is pointed; which means that it contains no line (or equivalently, $(x ∈ K~\land~ −x∈K) ~\to~ x=\vec 0$.
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Your question is very unclear. Please add more explanation and correctly format the math characters using Latex. – Joshua Ruiter Feb 09 '17 at 04:17
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2iam not able to find much information Mr joshua . thats why iam asking this question :\ . – MORAMREDDY RAKESH REDDY Feb 09 '17 at 04:24
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1Why is no answer accepted? – ViktorStein Jul 24 '20 at 02:44
2 Answers
Here is a picture (in 3D) of a cone which is not a pointed cone:
https://upload.wikimedia.org/wikipedia/commons/thumb/7/72/DoubleCone.png/1024px-DoubleCone.png
Here is a picture (in 3D) of a cone which is a pointed cone:
https://upload.wikimedia.org/wikipedia/commons/e/e7/Circular-pyramid.png
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It means there are no 2 points inside it which creates a line and the whole line is contained by the cone.
For instance, take $ \mathbb{R}^{2} $ it is clearly a cone yet it is not pointed as any line in $ \mathbb{R}^{2} $ is contained by $ \mathbb{R}^{2} $.
Yet if you take $ \mathbb{R}^{2}_{++} $, namely only the right up quarter of it (Where each coordinate is non negative) it is a cone clearly, moreover it is a pointed cone as there is no line contained in it.
Remember that a line is defined by all points which are defined by $ {x}_{1}, {x}_{2} $ and $ \theta \in \mathbb{R} $ in the following way:
$$ \theta {x}_{1} + \left( 1 - \theta \right) {x}_{2} $$
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