Sorry if I'm late, but usually if a quadratic has the form $ax^2+bx+c$ it can be factored as $(qx-d)(px-f)$ where q, d, f, and p are some numbers where $f*d=c, q*p=a$. In this case, $6x^2+7x-3$, -3 has factors -1 and 3, and 6 has factors 3 and 2. Now we must check to find b. If the factor is 2x-1, then the other factor would be 3x+3, multiplying this out would give a b-value of 3, not seven, so the quadratic becomes $(3x-1)(2x+3)$ as desired. In general, factoring mentally takes practice, and there is no sure way to accomplish it. The AC-method works to an extent, but often times some quadratic equations cannot be factored using rational numbers. Often times however, the easiest method is the quadratic formula, which I personally find myself using often.