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You have the following set of stamps:

  • 2 three-cent stamps
  • 3 five-cent stamps
  • 2 seven-cent stamps

Use a generating function to:

a) Find all postage amounts that can be formed using a subset of these stamps.

b) Find the number of ways each amount can be formed.

I'm not quite sure where to begin.

I assume the problem can be set up like this:

$3x_1+5x_2+7x_3=n$

where n is the amount of money and $x_1$ is the number of three-cent stamps, and so on.

Then, we also have that $0 \le x_1 \le 2, 0 \le x_2 \le 3$, and $0 \le x_3 \le 2$.

I've learned the following method for similar problems, but I'm clearly not understanding something because it doesn't seem to work...

If $x_1$ were not limited to between 0 and 2, it would create the function $1+x^3+x^6+x^9...$

However, since it is limited, I don't see how this could work. The same applies for $x_2$ and $x_3$. Could someone please explain to me in the simplest possible terms what it is that I am not understanding?

Irina Sokolova
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  • This is the very classical "dollar change problem". See for example (http://math.stackexchange.com/q/15521) or (http://www.cut-the-knot.org/ctk/GeneratingFunctions.shtml). – Jean Marie Oct 12 '16 at 22:51

2 Answers2

1

As you said, if $x_1$ were not limited by $0\le x_1\le 2$, then you would use the function $1+x^3+x^6+x^9+\dots$ . In order to account for $0\le x_1\le 2$, simply only use the first three terms of this series, $1+x^3+x^6$. Same for the other two variables.

The generating function is then $$ (1+x^3+x^6)(1+x^5+x^{10}+x^{15})(1+x^7+x^{14}) $$

In general, if you are counting solutions to the equation $x_1+\dots+x_k=n$, and each variable $x_i$ is restricted to some set $S$, the generating function for that variable is $\sum_{s\in S}x^s$. In your case, you have $3x_1+5x_2+7x_3=n$, and $0\le x_1\le 2$, so that $3x_1$ must be in the set $\{0,3,6\}$, leading to $x^0+x^3+x^6$.

Mike Earnest
  • 84,902
0

Consider the way in which you expand this product $$ \left( {1 + x^{\,3} } \right)\left( {1 + x^{\,5} } \right) = 1x^{\,0} + 1x^{\,3} + 1x^{\,5} + 1x^{\,8} $$ and then this $$ \begin{gathered} \left( {1 + x^{\,3} } \right)\left( {1 + x^{\,3} } \right)\left( {1 + x^{\,5} } \right) = \left( {1 + x^{\,3} } \right)^{\,2} \left( {1 + x^{\,5} } \right) = \hfill \\ = 1 + 2x^{\,3} + 1x^{\,5} + 1x^{\,6} + 2x^{\,8} + 1x^{\,11} \hfill \\ \end{gathered} $$ You will easily recognize that $$ \left( {1 + x^{\,3} } \right)^{\,2} \left( {1 + x^{\,5} } \right)^{\,3} \left( {1 + x^{\,7} } \right)^{\,2} $$ is the answer to your question, when in the number of ways to compose a given amount you do not make distinction as for the order in which the stamp are placed, but you make distinction as for the ways in which you can choose a stamp to be part of the amount. For example you have $2x^3$ and $1x^6$.

G Cab
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