Fast way to multiply permutation groups?

Asked Jan 06 '16 at 20:22

Active Jan 06 '16 at 20:22

Viewed 513 times

I'm having some trouble with permutation group multiplication. When multiplying permutation groups, I always follow the method described in this post: Multiplication in Permutation Groups Written in Cyclic Notation

Suppose, we have two cycles:

a ⇨ (opqrstu)(hijklmn)(abcdefg)

b ⇨ (gmr)(fku)(eiq)(dnt)(clp)(bjs)(aho)

Suppose I would like to calculate some products of these cycles: a², a³, ab, ab², a²b³, ... Is there a 'fast' / computer based way to calculate these results? I suppose you could do it by hand, but that's going to take a very long time and is prone to errors...

edited Apr 13 '17 at 12:20

Community

asked Jan 06 '16 at 20:22

Laurent Loots

3

Seems like you are asking about multiplying permutations, not permutation groups. – Thomas Andrews Jan 06 '16 at 20:35
1

Using computer, you can multiply permutations in GAP - see this documentation – Olexandr Konovalov Jan 06 '16 at 20:58

Fast way to multiply permutation groups?

0 Answers0