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Let $f$ a continuous function on $\mathbb R$ such that $f(0)=f(2)$. Answer by true or false. There exists $\alpha\in[0,1]$ such that $f(\alpha)=f(\alpha+1)$.

I think that it's wrong but I'm not able to find a counter exemple.

Asaf Karagila
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idm
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1 Answers1

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Hint:

consider $g(x)=f(x)-f(x+1)$, note we always have $g(0)=-g(1)$. Discuss the value of $g(0),g(1)$. Also remember intermediate value theorem.

John
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