It is known that if we only consider the first four decimal digits of the following (no rounding), we have that this holds:$$\pi^4+\pi^5=e^6\label1\tag1$$However, if we use even one more decimal place, we find that it does not, in fact, hold. So obviously, I want to find some $\epsilon$ (for $\epsilon\gt0$, since $\pi^4+\pi^5\lt e^6$) such that $\eqref1$ is true.
In other words, I want to find an $\epsilon$ such that$$(\pi+\epsilon)^4+(\pi+\epsilon)^5=e^6$$which means that I need to find the real root of the quintic$$x^5+x^4-e^6=0\qquad\boxed{\small{\text{Where }e\text{ is Euler's number}}}$$So I want to know if there is a way to solve quintics of the form$$ax^5+bx^4+c=0$$I specifically have in this case$$\boxed{a=1\\b=1\\c=-e^6}$$however if a general form of the quintic is known, that would be appreciated.