show that $(\sqrt n)^\sqrt n=o(2^{n^{0.6}})$
i just know that small o-complexity of $\sqrt n=o(n)$ but how to prove this
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show that $(\sqrt n)^\sqrt n=o(2^{n^{0.6}})$
i just know that small o-complexity of $\sqrt n=o(n)$ but how to prove this
